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1 // 2 // main.c 3 // 统计输入单词数 4 // 5 // Created by LongMa on 2019/6/27. 6 // Copyright © 2019 . All rights reserved. 7 // 8 9 #include10 #include 11 12 int main(int argc, const char * argv[]) {13 14 //输入一个英文句子,英文句以空格分隔。统计句子中有多少个单词。15 //eg:how are you,有3个单词16 char string[80];17 printf("请输入英文句子:");18 gets(string);19 20 char c;21 char kongGe[2] = " ";22 int word = 0;23 int num = 0;24 25 for (int i = 0; (c = string[i]) != '\0'; i++) {26 if (c == 32) {//当前位为空格(ASCII码值为32)时,word记录为0.注意:xcode中strcmp(&c, " ")为-120,不为0,strcmp比较的是字符串,不能比较字符和字符串!27 printf("%d,%d是否相等:%d\n",c,kongGe[0], strcmp(&kongGe[0], &c));28 word = 0;29 }else{//当前位不为空格时30 if(0 == word){//上一位为空格/第一位是字母时31 num += 1;32 word = 1;33 }else{//上一位不为空格时,不能算一个单词34 //do nothing35 }36 }37 }38 39 printf("语句:%s\n", string);40 printf("单词数:%d个",num);41 return 0;42 }
log:
请输入英文句子:warning: this program uses gets(), which is unsafe.how are you32,32是否相等:-12032,32是否相等:-120语句:how are you单词数:3个Program ended with exit code: 0
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